If alpha and beta are the roots of ax-2 - bx-c-0- a neq 0 then the wrong statement isalpha -2-beta -2-dfrac-b-2-2ac-a-2-alpha beta -frac-c-a-alpha -beta -frac-b-a-frac-1-alpha -frac-1-beta -frac-b-c-

Question

Toppr Admin · Accepted Answer

We know that sum of roots -x2212-ba and product of roots is-xA0- caHence option -C- is wrong statement-

If $α$ and $β$ are the roots of $a x^{2} + b x + c = 0, a \neq 0$ then the wrong statement is
$α^{2} + β^{2} = \frac{b^{2} - 2 a c}{a^{2}}$
$α β = \frac{c}{a}$
$α + β = \frac{b}{a}$
$\frac{1}{α} + \frac{1}{β} = - \frac{b}{c}$

We know that sum of roots $= - \frac{b}{a}$ and product of roots is $\frac{c}{a}$
Hence option (C) is wrong statement.

If α and β are the roots of ax2+bx+c=0,a≠0 then the wrong statement isα2+β2=b2−2aca2αβ=caα+β=ba1α+1β=−bc

We know that sum of roots =−ba and product of roots is caHence option (C) is wrong statement.

If $α$ and $β$ are the roots of $a x^{2} + b x + c = 0, a \neq 0$ then the wrong statement is
$α^{2} + β^{2} = \frac{b^{2} - 2 a c}{a^{2}}$
$α β = \frac{c}{a}$
$α + β = \frac{b}{a}$
$\frac{1}{α} + \frac{1}{β} = - \frac{b}{c}$

We know that sum of roots $= - \frac{b}{a}$ and product of roots is $\frac{c}{a}$
Hence option (C) is wrong statement.