If displaystyle begin-bmatrix- x - 1 y - 2 end-bmatrix- - displaystyle begin-bmatrix- y - 1 8 - 0 end-bmatrix- - displaystyle begin-bmatrix- 2 - 0 -x - 2 end-bmatrix- then the values of x and y respectively are 5 and 15 and 33 and 23 and 4

Question

If displaystyle begin-bmatrix- x - 1  y - 2 end-bmatrix-  - displaystyle begin-bmatrix- y - 1  8 - 0 end-bmatrix- - displaystyle begin-bmatrix- 2 - 0  -x - 2 end-bmatrix-  then the values of x and  y respectively are 5  and 15 and 33 and 23 and 4

Toppr Admin · Accepted Answer

The correct option is B 5 and 3On comparing- we getx-x2212-y-2-xA0-y-x2212-8-x2212-xOn solving both the equations- we get-xA0-x-5 and y-3-

$x$	$8$	$X_{1}$	$16$	$X_{2}$	$80$
$y$	$Y_{1}$	$4$	$5$	$2$	$Y_{2}$

If $[\begin{matrix} x & 1 y & 2 \end{matrix}]$ $- [\begin{matrix} y & 1 8 & 0 \end{matrix}] =$ $[\begin{matrix} 2 & 0 - x & 2 \end{matrix}],$ then the values of $x$ and $y$ respectively are
$5$ and $1$
$5$ and $3$
$3$ and $2$
$3$ and $4$

The correct option is B $5$ and $3$
On comparing, we get
$x - y = 2,$ $y - 8 = - x$
On solving both the equations, we get
$x = 5$ and $y = 3$ .

If [x1y2] −[y180]= [20−x2], then the values of x and y respectively are 5 and 15 and 33 and 23 and 4

The correct option is B 5 and 3On comparing, we getx−y=2, y−8=−xOn solving both the equations, we get x=5 and y=3.

If $[\begin{matrix} x & 1 y & 2 \end{matrix}]$ $- [\begin{matrix} y & 1 8 & 0 \end{matrix}] =$ $[\begin{matrix} 2 & 0 - x & 2 \end{matrix}],$ then the values of $x$ and $y$ respectively are
$5$ and $1$
$5$ and $3$
$3$ and $2$
$3$ and $4$

The correct option is B $5$ and $3$
On comparing, we get
$x - y = 2,$ $y - 8 = - x$
On solving both the equations, we get
$x = 5$ and $y = 3$ .