If ab=13,bc=2,cd=12,de=3 and ef=14, then what is the value of abcdef ?
278
38
34
274
A
38
B
278
C
34
D
274
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Solution
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Given ab=13⇒a=b3
bc=2⇒c=b2
cd=12⇒d=2c⇒d=2×b2=b
de=3⇒e=d3⇒e=b3
ef=14⇒f=4e⇒f=4b3
∴abcdef=b3×b×b2b×b3×4b3=38
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