If displaystyle sqrt-12-xsqrt-2-2sqrt-2-2- then x-68-8-6

Question

Toppr Admin · Accepted Answer

Given- -x221A-12-x-x221A-2-2-x221A-2-x2212-2On squaring both sides- we get-x21D2-12-x-x221A-2-8-4-x2212-8-x221A-2-x21D2-12-x-x221A-2-12-x2212-8-x221A-2-x21D2-x-x221A-2-x2212-8-x221A-2Cancelling -x221A-2 on both the sides- we getx-x2212-8

$X$	$2 - 4$	$4 - 6$	$6 - 8$	$8 - 10$	$10 - 12$	$12 - 14$	$14 - 16$
$F$	$1$	$2$	$2$	$3$	$6$	$3$	$2$

If $\sqrt{12 + x \sqrt{2}} = 2 \sqrt{2} - 2$ , then find $x$ .
$6$
$8$
$- 8$
$- 6$

Given, $\sqrt{12 + x \sqrt{2}} = 2 \sqrt{2} - 2$
On squaring both sides, we get
$\Rightarrow 12 + x \sqrt{2} = 8 + 4 - 8 \sqrt{2}$
$\Rightarrow 12 + x \sqrt{2} = 12 - 8 \sqrt{2}$
$\Rightarrow x \sqrt{2} = - 8 \sqrt{2}$
Cancelling $\sqrt{2}$ on both the sides, we get
$x = - 8$

If √12+x√2=2√2−2, then find x.68−8−6

Given, √12+x√2=2√2−2On squaring both sides, we get⇒12+x√2=8+4−8√2⇒12+x√2=12−8√2⇒x√2=−8√2Cancelling √2 on both the sides, we getx=−8

If $\sqrt{12 + x \sqrt{2}} = 2 \sqrt{2} - 2$ , then find $x$ .
$6$
$8$
$- 8$
$- 6$

Given, $\sqrt{12 + x \sqrt{2}} = 2 \sqrt{2} - 2$
On squaring both sides, we get
$\Rightarrow 12 + x \sqrt{2} = 8 + 4 - 8 \sqrt{2}$
$\Rightarrow 12 + x \sqrt{2} = 12 - 8 \sqrt{2}$
$\Rightarrow x \sqrt{2} = - 8 \sqrt{2}$
Cancelling $\sqrt{2}$ on both the sides, we get
$x = - 8$