If displaystyle y-frac-ax-b-left - x-1 right -left - x-4 right - has a turning value displaystyle left - 2-1 right - a - b -a -0-b-0a -1-b-0a -0-b-1a -1-b-1

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Toppr Admin · Accepted Answer

Given- y-ax-b-x-x2212-1-x-x2212-4-Taking log both side- logy-log-ax-b-x2212-log-x-x2212-1-x2212-log-x-x2212-4-Differentiating w-r-t x both side-dyy-dx-aax-b-x2212-1x-x2212-1-x2212-1x-x2212-4Given turning value at -2-x2212-1-x21D2-y-x2032-2-0-x21D2-a2a-b-x2212-12-0-x21D2-b-0Also the given curve will pass through -2-x2212-1-x21D2-x2212-1-2a1-x2212-2-x21D2-a-1

If y=ax+b(x−1)(x−4) has a turning value at (2,−1) find a & b .a=0,b=0a=1,b=0a=0,b=1a=1,b=1

Given, y=ax+b(x−1)(x−4)Taking log both side, logy=log(ax+b)−log(x−1)−log(x−4)Differentiating w.r.t x both side,dyy.dx=aax+b−1x−1−1x−4Given turning value at (2,−1)⇒y′(2)=0⇒a2a+b−12=0⇒b=0Also the given curve will pass through (2,−1)⇒−1=2a1.−2⇒a=1

If $y = \frac{a x + b}{(x - 1) (x - 4)}$ has a turning value at $(2, - 1)$ find $a$ & $b$ .
$a = 0, b = 0$
$a = 1, b = 0$
$a = 0, b = 1$
$a = 1, b = 1$