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Standard XII
Maths
Question
If
z
1
and
z
2
are two non-zero complex numbers such that
|
z
1
+
z
2
|
=
|
z
1
|
+
|
z
2
|
, then
a
r
g
z
1
−
a
r
g
z
2
is equal to
−
π
π
/
2
−
π
/
2
0
A
0
B
π
/
2
C
−
π
D
−
π
/
2
Open in App
Solution
Verified by Toppr
Given
z
1
+
z
2
|
=
|
z
1
|
+
|
z
2
|
⇒
|
z
1
|
2
+
|
z
2
|
2
+
2
R
e
(
z
1
¯
z
2
)
=
|
z
1
|
2
+
|
z
2
|
2
+
2
|
z
1
|
|
z
2
|
⇒
R
e
(
z
1
¯
z
2
)
=
|
z
1
|
|
z
2
|
⇒
R
e
(
z
1
¯
z
2
)
=
|
z
1
¯
z
2
|
(or
R
e
(
¯
z
1
z
2
)
=
|
¯
z
1
z
2
|
)
⇒
z
1
¯
z
2
=
R
+
⇒
A
r
g
(
z
1
¯
z
2
)
=
A
r
g
(
¯
z
1
z
2
)
=
0
⇒
A
r
g
z
1
+
A
r
g
¯
z
2
=
A
r
g
¯
z
1
+
A
r
g
z
2
=
0
⇒
A
r
g
z
1
−
A
r
g
z
2
=
−
A
r
g
z
1
+
A
r
g
z
2
=
0
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