If sec 5A - - - cosec-A - - - 36-circ- where 5A is an acute angle- the value of A-

Question

Toppr Admin · Accepted Answer

Sec5A-cosec-A-36-x2218-x21D2-sec5A-sec-90-x2218-x2212-A-36-x2218-x21D2-sec5A-sec-54-x2218-x2212-A-xA0-x21D2-5A-54-x2218-x2212-A-x21D2-6A-54-x2218-x21D2-A-9-x2218-xA0-

If $s e c 5 A = c o s e c (A + 36^{\circ})$ where 5A is an acute angle, find the value of A.

$s e c 5 A = c o s e c (A + 36^{\circ})$

$\Rightarrow s e c 5 A = s e c (90^{\circ} - (A + 36^{\circ}))$

$\Rightarrow s e c 5 A = s e c (54^{\circ} - A)$

$\Rightarrow 5 A = 54^{\circ} - A \Rightarrow 6 A = 54^{\circ} \Rightarrow A = 9^{\circ}$

If sec5A=cosec(A+36∘) where 5A is an acute angle, find the value of A.

sec5A=cosec(A+36∘)⇒sec5A=sec(90∘−(A+36∘))⇒sec5A=sec(54∘−A) ⇒5A=54∘−A⇒6A=54∘⇒A=9∘

If $s e c 5 A = c o s e c (A + 36^{\circ})$ where 5A is an acute angle, find the value of A.

$s e c 5 A = c o s e c (A + 36^{\circ})$

$\Rightarrow s e c 5 A = s e c (90^{\circ} - (A + 36^{\circ}))$

$\Rightarrow s e c 5 A = s e c (54^{\circ} - A)$

$\Rightarrow 5 A = 54^{\circ} - A \Rightarrow 6 A = 54^{\circ} \Rightarrow A = 9^{\circ}$