If tan -theta-cot-theta- and 0-circ-leq-theta-leq-90-circ- state the value of theta45-circ-30-circ-90-circ-60-circ-

Question

Toppr Admin · Accepted Answer

Tan-x3B8-cot-x3B8-tan-x3B8-1tan-x3B8-tan2-x3B8-1tan-x3B8-xB1-1Value of tan-xA0-x3B8- is positive in first quadrant-Neglect the negative value as -x3B8- is acute-tan-x3B8-1tan-x3B8-tan-xA0-45o-x21D2-x3B8-45-x2218-

If $t a n θ = c o t θ$ and $0^{\circ} \leq θ \leq 90^{\circ}$ , state the value of $θ$
$45^{\circ}$
$30^{\circ}$
$90^{\circ}$
$60^{\circ}$

$t a n θ = c o t θ$
$t a n θ = \frac{1}{t a n θ}$
$t a n^{2} θ = 1$
$t a n θ = \pm 1$
Value of $t a n θ$ is positive in first quadrant.
Neglect the negative value as $θ$ is acute.
$t a n θ = 1$
$t a n θ = t a n 45^{o}$
$\Rightarrow θ = 45^{\circ}$

If tanθ=cotθ and 0∘≤θ≤90∘, state the value of θ45∘30∘90∘60∘

tanθ=cotθtanθ=1tanθtan2θ=1tanθ=±1Value of tan θ is positive in first quadrant.Neglect the negative value as θ is acute.tanθ=1tanθ=tan 45o⇒θ=45∘

If $t a n θ = c o t θ$ and $0^{\circ} \leq θ \leq 90^{\circ}$ , state the value of $θ$
$45^{\circ}$
$30^{\circ}$
$90^{\circ}$
$60^{\circ}$

$t a n θ = c o t θ$
$t a n θ = \frac{1}{t a n θ}$
$t a n^{2} θ = 1$
$t a n θ = \pm 1$
Value of $t a n θ$ is positive in first quadrant.
Neglect the negative value as $θ$ is acute.
$t a n θ = 1$
$t a n θ = t a n 45^{o}$
$\Rightarrow θ = 45^{\circ}$