Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XII
Maths
Question
If
X
=
{
4
n
−
3
n
−
1
:
n
∈
N
}
and
Y
=
{
9
(
n
−
1
)
:
n
∈
N
}
, where N is the set of natural numbers, then
X
∪
Y
is equal to:
N
Y
X
Y
−
X
A
Y
B
Y
−
X
C
N
D
X
Open in App
Solution
Verified by Toppr
X
=
{
0
,
9
,
54...
}
Y
=
{
0
,
9
,
18
,
27...
}
Hence
X
is a subset of
Y
Therefore
X
∪
Y
=
Y
Was this answer helpful?
42
Similar Questions
Q1
If
X
=
{
4
n
−
3
n
−
1
:
n
∈
N
}
&
Y
=
{
9
(
n
−
1
)
:
n
∈
N
}
,
where
N
is the set of natural numbers, then
X
∪
Y
is equal to:
View Solution
Q2
If
X
=
{
4
n
−
3
n
−
1
:
n
∈
N
}
and
Y
=
{
9
(
n
−
1
)
:
n
∈
N
}
where
N
is the set of natural numbers, then
X
∪
Y
is equal to
View Solution
Q3
If
X
=
{
4
n
−
3
n
−
1
:
n
ϵ
N
}
a
n
d
Y
=
{
9
(
n
−
1
)
:
n
ϵ
N
}
,
where N is the set of natural numbers, then
X
∪
Y
is equal to:
View Solution
Q4
If
X
=
{
4
n
−
3
n
−
1
:
n
∈
N
}
and
Y
=
{
9
(
n
−
1
)
:
n
∈
N
}
, where
N
is the set of natural numbers, then
X
∪
Y
is equal to:
View Solution
Q5
If
X
=
{
4
n
−
3
n
−
1
:
n
ϵ
N
}
a
n
d
Y
=
{
9
(
n
−
1
)
:
n
ϵ
N
}
,
where N is the set of natural numbers, then
X
∪
Y
is equal to:
View Solution