If x-sqrt-6-sqrt-5- then displaystyle x-2-frac-1-x-2-11122sqrt-30-

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If $x = \sqrt{6} - \sqrt{5}$ , then $x^{2} + \frac{1}{x^{2}} =$ ?
$11$
$1$
$22$
$\sqrt{30}$

11

22

\sqrt{30}

1

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Solution

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$x = \sqrt{6} - \sqrt{5}$ .

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If x=√6−√5, then x2+1x2=?11122√30

x=√6−√5.

If $x = \sqrt{6} - \sqrt{5}$ , then $x^{2} + \frac{1}{x^{2}} =$ ?
$11$
$1$
$22$
$\sqrt{30}$

$x = \sqrt{6} - \sqrt{5}$ .