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"(ii) \\( \\angle \\mathrm { PQR } = \\angle \\mathrm { SRQ } \\)\n10. In the given figure, we have \\( \\mathrm { AC } \\perp \\mathrm { CD } , \\mathrm { BC } + \\mathrm { CD } \\) and \\( \\mathrm { DA } = \\mathrm { DR } \\)\nProve that \\( \\mathrm { CA } = \\mathrm { CB } \\).\nIHint \\( = \\) Prove that \\( \\Delta \\mathrm { DCA } = \\mathrm { ADCBI } \\)\n1. In the adjoining figure, \\( \\Delta \\mathrm { ABC } \\) is an isosedes triangle in which"

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