ii) $ \operatorname { ar } ( \mathrm { AXS } ) = \frac { 1 } { 2 } $ ar $ ( \mathrm { PQRS } ) $ $ Q B $ Fiy. 9.17

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

Prove that

a r (△ A X S) = \frac{1}{2} a r (P Q R S)

in the adjoining figure.

View Solution

PQRS and ABRS are parallelogram and x is any point on the side BR. show that
(I) ar(PQRS) = ar(ABRS)
(ii) ar

(Δ A X S) = \frac{1}{2} a r (P Q R S)

View Solution

In figure,

P Q R S

and

A B R S

are parallelogram and

X

is any point on side

B R

. Show that
(i)

a r (P Q R S) = a r (A B R S)

(ii)

a r (A X Z) = \frac{1}{2} a r (P Q R S)

View Solution

Q. With reference to FIIs, consider the following statements:Which of the statements given above is/are correct?

View Solution

In the given figure, PQRS and ABRS are parallelograms and X is any point on side BR. Show that

(i) area (PQRS) $=$ area (ABRS)

(ii) area (AXS) $= \frac{1}{2}$ area (PQRS)

View Solution

ii) \( \operatorname { ar } ( \mathrm { AXS } ) = \frac { 1 } { 2 } \) ar \( ( \mathrm { PQRS } ) \) \( Q B \) Fiy. 9.17