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ii) Calcium Hydroxide reacts with ammonium chloride to give ammonia according to the equation. Ca(OH)2 + 2 NH4Cl --> CaCl2 + 2NH3 + 2H20. If 5.35 g of ammonium chloride is used calculate : the weight of calcium chloride formed. the volume at STP of ammonia liberated at the same time. [H =1, N = 14, 0 =16, Cl = 35.5, Ca =40]. SECTION - B

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Q1

Calcium hydroxide reacts with ammonium chloride to give ammonia, according to the following equation:

$Ca {(OH)}_{2} + 2 {NH}_{4} Cl \to {CaCl}_{2} + 2 {NH}_{3} + 2 H_{2} O$

If $5.35 g$ of ammonium chloride is used, calculate the volume at STP of ammonia liberated.

$[H = 1, N = 14, O = 16, Cl = 35.5, Ca = 40]$

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Q2

Calcium hydroxide reacts with ammonium chloride to give ammonia, according to the following equation:

$Ca {(OH)}_{2} + 2 {NH}_{4} Cl \to {CaCl}_{2} + 2 {NH}_{3} + 2 H_{2} O$

If $5.35 g$ of ammonium chloride is used, calculate the weight of calcium chloride is formed.

$[H = 1, N = 14, O = 16, Cl = 35.5, Ca = 40]$

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Q3

Calcium hydroxide reacts with ammonium chloride to give ammonia, according to the following equation:

$Ca {(OH)}_{2} + 2 {NH}_{4} Cl \to {CaCl}_{2} + 2 {NH}_{3} + 2 H_{2} O$

If $5.35 g$ of ammonium chloride is used, calculate:

(a) The mass of calcium chloride formed

(b) The volume, at STP of ${NH}_{3}$ liberated.

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Q4

How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

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[N=14, H=1, O=16, S=32, Cl=35.5]

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Q5

Calculate the weight of ammonia gas.
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