In a bundle of 154 shirts- the number of white shirts is 3 than the number of red shirts- but 5 than the green shirts- Then how many red shirts are there-

Letthenumberofwhiteshirtsbexredshirts-x-3greenshirts-x-x2212-5Given-Totalshirts-x-x-3-x-x2212-5-1543x-x2212-2-154x-1563-52redshirts-x-3-55

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Standard VIII

Mathematics

Applications (Word Problem)

Question

In a bundle of $154$ shirts, the number of white shirts is $3$ less than the number of red shirts, but $5$ more than the green shirts. Then how many red shirts are there?

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$L e t t h e n u m b e r o f w h i t e s h i r t s b e x r e d s h i r t s = x + 3 g r e e n s h i r t s = x - 5 G i v e n, T o t a l s h i r t s = x + x + 3 + x - 5 = 154 3 x - 2 = 154 x = \frac{156}{3} = 52 r e d s h i r t s = x + 3 = 55$

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In a bundle of 154 shirts, the number of white shirts is 3 less than the number of red shirts, but 5 more than the green shirts. Then how many red shirts are there?

Letthenumberofwhiteshirtsbexredshirts=x+3greenshirts=x−5Given,Totalshirts=x+x+3+x−5=1543x−2=154x=1563=52redshirts=x+3=55

In a bundle of $154$ shirts, the number of white shirts is $3$ less than the number of red shirts, but $5$ more than the green shirts. Then how many red shirts are there?

$L e t t h e n u m b e r o f w h i t e s h i r t s b e x r e d s h i r t s = x + 3 g r e e n s h i r t s = x - 5 G i v e n, T o t a l s h i r t s = x + x + 3 + x - 5 = 154 3 x - 2 = 154 x = \frac{156}{3} = 52 r e d s h i r t s = x + 3 = 55$