0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

In a capacitive circuit, dielectrics materials are placed between the plates of capacitors to
  1. Speed the current flow
  2. Slow the current flow
  3. Reduce change leakage from the capacitor
  4. increase change leakage from the capacitor
  5. Increase capacitance of the capacitor
  6. Decrease capacitance of the capacitor

A
increase change leakage from the capacitor
B
Slow the current flow
C
Increase capacitance of the capacitor
D
Speed the current flow
E
Reduce change leakage from the capacitor
F
Decrease capacitance of the capacitor
Solution
Verified by Toppr

When a dielectric material with dielectric constant K is placed in between the plates of a capacitor, the capacitance will be increased by factor K. Thus, the option E will be correct.

Was this answer helpful?
0
Similar Questions
Q1
In a capacitive circuit, dielectrics materials are placed between the plates of capacitors to
View Solution
Q2
The capacitance of parallel-plate capacitor is 4μF. If a dielectric material of dielectric constant 16 is placed between the plates then the new capacitance will be :
View Solution
Q3
A parallel plate capacitor with no dielectric between the plates is connected to the constant voltage source. How would capacitance and charge change if the dielectric constant K=2 is inserted between the plates?
(C0 and Q0 are the capacitance and charge of the capacitor before the introduction of the dielectric.)
View Solution
Q4
For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 34d, where d is the separation between the plates of the parallel plate capacitor. The new capacitance (C) in terms of the original capacitance (C0) is given by the following relation:
View Solution
Q5
Consider a parallel-plate capacitor of capacitance 10 μF with air filled in the gap between the plates. Now, one half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in the figure. The capacitance of the capacitor changes to

View Solution