In a chamber- a uniform magnetic field of 6-5 G -1- G- - 10-4- T- is maintained- An electron is shot into the field with a speed of 4-8- times- 10-6- m- s-1- normal to the field- Explain why the path of the electron is a circle- Determine the radius of the circular orbit- -e- - 1-5- times- 10-19- C- m-e- - 9-1- times-10-31- kg-

Question

Toppr Admin · Accepted Answer

Angle between electron and the magnetic field is 90oF-eVBsin-x3B8- where e-charge on the electron-F provide centripetal force to moving electron-hence- it starts moving the circular path-Fc-mv2-rin equilibrium- F-Fc-x21D2-r-4-2-xA0-cm

In a chamber, a uniform magnetic field of 6.5 G (1G=10−4T) is maintained. An electron is shot into the field with a speed of 4.8×106ms−1 normal to the field. Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e=1.5×10−19C,me=9.1×10−31kg)

Angle between electron and the magnetic field is 90oF=eVBsinθ, where e=charge on the electron.F provide centripetal force to moving electron.hence, it starts moving the circular path.Fc=mv2/rin equilibrium, F=Fc⇒r=4.2 cm

Angle between electron and the magnetic field is $90^{o}$
$F = e V B s i n θ$ , where e=charge on the electron.
F provide centripetal force to moving electron.
hence, it starts moving the circular path.
$F_{c} = m v^{2} / r$
in equilibrium, $F = F_{c}$
$\Rightarrow r = 4.2 c m$