Question

In a circle of diameter $40cm$ the length of a chord is $20cm$. Find the length of minor arc of the chord.

Answer 1

length of cord = radius = 20 cm.

$△ABC$ is equilateral triangle.

$\theta ={60}^0$

We know, $S=r\theta$

$S=20\times {60}^0\times \frac{\pi }{180}=\frac{20}{3}\pi cm.$