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In a conductor electrons are flowing from B to A. What is the direction of conventional current? Give justification for your answer.
A steady current of $$1$$ ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor in $$1$$ second. (Charge on electron $$1.6 \times 10^{-19}$$ coulomb).

Solution
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The direction of conventional current is A to B, i.e. opposite to the direction of flow of electrons. In a metal, flow of electrons carrying negative charge constitutes the current. Direction of flow of electrons gives the direction of electronic current by convention, the direction of flow of positive charge is taken as the direction of conventional current.
Charge $$ = q = ne $$
For $$q = 1 $$ coulomb, $$ n = \dfrac{1C}{1.6 \times 10^{-19}\ C} = \dfrac{10^{19}}{1.6} = 6.25 \times 10^{18}$$ electrons

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