In a diffraction pattern due to a single slit of width ′a′, the first minimum is observed at an angle 30o when light of wavelength 5000˚A is incident on the slit. The first secondary maximum is observed at an angle of :
sin−1(14)
sin−1(23)
sin−1(34)
sin−1(12)
A
sin−1(23)
B
sin−1(12)
C
sin−1(34)
D
sin−1(14)
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Solution
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For first minima: sin300=λa=12
First secondary maxima will be at:
sinθ=3λ2a=32×12
⇒θ=sin−1(34)
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