In a gas- 10- molecules have a velocity of 2 km-sec and 8- molecules have a velocity of 1-5 km-sec and 82- molecules have a velocity 1 km- per sec- The probable velocity of molecules is1-5 km-sec-1 km-sec-2 km-sec-15 km-sec-

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Vavg-10-xD7-2-8-xD7-1-5-82-xD7-1100-1-14-Vavg-x221A-8RT-x3C0-M-and VMP-x221A-2RTM-x2234-VavgVMP-2-x221A-x3C0-x2234-VMP-x221A-x3C0-2-xD7-Vavg-1 km-sec

In a gas, $10$ % molecules have a velocity of $2 k m / s e c$ and $8$ % molecules have a velocity of $1.5 k m / s e c$ and $82$ % molecules have a velocity $1 k m$ . per sec. The most probable velocity of molecules is
$1.5 k m / s e c .$
$1 k m / s e c .$
$2 k m / s e c .$
$15 k m / s e c .$

$V_{a v g} = \frac{10 \times 2 + 8 \times 1.5 + 82 \times 1}{100} = 1.14$

$V_{a v g} = \sqrt{\frac{8 R T}{π M}}$ and $V_{M P} = \sqrt{\frac{2 R T}{M}}$

$∴ \frac{V_{a v g}}{V_{M P}} = \frac{2}{\sqrt{π}}$

$∴ V_{M P} = \frac{\sqrt{π}}{2} \times V_{a v g} = 1$ $k m / s e c$

In a gas, 10% molecules have a velocity of 2 km/sec and 8% molecules have a velocity of 1.5 km/sec and 82% molecules have a velocity 1km. per sec. The most probable velocity of molecules is1.5 km/sec.1 km/sec.2 km/sec.15 km/sec.

Vavg=10×2+8×1.5+82×1100=1.14 Vavg=√8RTπM and VMP=√2RTM ∴VavgVMP=2√π ∴VMP=√π2×Vavg=1 km/sec

In a gas, $10$ % molecules have a velocity of $2 k m / s e c$ and $8$ % molecules have a velocity of $1.5 k m / s e c$ and $82$ % molecules have a velocity $1 k m$ . per sec. The most probable velocity of molecules is
$1.5 k m / s e c .$
$1 k m / s e c .$
$2 k m / s e c .$
$15 k m / s e c .$

$V_{a v g} = \frac{10 \times 2 + 8 \times 1.5 + 82 \times 1}{100} = 1.14$

$V_{a v g} = \sqrt{\frac{8 R T}{π M}}$ and $V_{M P} = \sqrt{\frac{2 R T}{M}}$

$∴ \frac{V_{a v g}}{V_{M P}} = \frac{2}{\sqrt{π}}$

$∴ V_{M P} = \frac{\sqrt{π}}{2} \times V_{a v g} = 1$ $k m / s e c$