0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Solution
Verified by Toppr

Given:
H=28m, R=52=2.5cm =0.025m (2.5100)

CSA of pipe (cylindrical)=2πrh

=2×227×0.025×28m2

=4.4m2

Was this answer helpful?
32
Similar Questions
Q1
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.
View Solution
Q2

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.
[π=227]

View Solution
Q3
In a water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.
View Solution
Q4
Question 8
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface of the system.
[Assume π=227]
View Solution
Q5
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. The total radiating surface in the system.
View Solution