In a non-linear electric field- a charged particle returns to its initial point sometime after it is released in the field- The work done by the field is given byinfty0Some constant neq 0None of these

Question

Toppr Admin · Accepted Answer

Let the potential at its initial point be-xA0-VAwork done-xA0-VB-x2212-VA-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-VA-x2212-VA-x2235-sinceVB-VA-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-0Thus the work done by the field is zero-Option -B- is correct-

In a non-linear electric field, a charged particle returns to its initial point sometime after it is released in the field. The work done by the field is given by
$\infty$
$0$
Some constant $\neq 0$
None of these

Let the potential at its initial point be $V_{A}$
work done $= V_{B} - V_{A}$
$= V_{A} - V_{A} (∵ s i n c e V_{B} = V_{A})$
$= 0$
Thus the work done by the field is zero.

Option (B) is correct.

In a non-linear electric field, a charged particle returns to its initial point sometime after it is released in the field. The work done by the field is given by∞0Some constant ≠0None of these

Let the potential at its initial point be VAwork done =VB−VA =VA−VA(∵sinceVB=VA) =0Thus the work done by the field is zero.Option (B) is correct.

In a non-linear electric field, a charged particle returns to its initial point sometime after it is released in the field. The work done by the field is given by
$\infty$
$0$
Some constant $\neq 0$
None of these

Let the potential at its initial point be $V_{A}$
work done $= V_{B} - V_{A}$
$= V_{A} - V_{A} (∵ s i n c e V_{B} = V_{A})$
$= 0$
Thus the work done by the field is zero.

Option (B) is correct.