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Question

In a photoelectric experiment the stopping potential for the incident light of wavelength 4000˚A is 2 volt. If the wavelength be changed to 3000˚A, the stopping potential will be :
  1. 2 V
  2. Zero
  3. Less than 2 V
  4. More than 2 V

A
2 V
B
Less than 2 V
C
More than 2 V
D
Zero
Solution
Verified by Toppr

Photoelectric Effect,

KEmax=hvWo

The stopping potential,

Vse=KEmax

Vse=hvWo

Vse=hcλWo

From the above equation, as λ decreases, Vs increases.
Hence Vs>2V

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