0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# In a photoemissive cell with exciting wavelength λ, the fastest electron has speed v. If the exciting wavelength is changed by 3λ/4, the speed of the fastest emitted electron will be :v(3/4)1/2v(4/3)1/2less than v(4/3)1/2greater than v(4/3)1/2

A
less than v(4/3)1/2
B
v(4/3)1/2
C
v(3/4)1/2
D
greater than v(4/3)1/2
Solution
Verified by Toppr

#### From E=W0+12mv2max⇒vmax=√2Em−2W0mwhere E=hcλIf wavelength of incident light charges from λ to 3λ4 (Decreases)Let energy of incident light charges from E and speed of fastest electron changes from v to v′ thenv′=√2E′m−2W0mAs E∝1λ⇒E′43EHence v′=  ⎷2(43)Em−2W0m⇒v′=(4/3)1/2√2Em−2W0m(4/3)1/2So, v′>(4/3)1/2v

Was this answer helpful?
7
Similar Questions
Q1
In a photoemissive cell with executing wavelength λ , the fastest electron has speed v. If the exciting wavelength is changed to 3λ4, the speed of the fastest emitted electron will be
View Solution
Q2
In a photo-emissive cell, with exciting wavelength λ, the fastest electron has speed v. If the exciting wavelength is changed to 3λ4, the speed of the fastest emitted electron will be
View Solution
Q3
In a photocell, with excitation wavelength λ, the faster electrons has speed v. If the excitation wavelength is changed to 3λ/4, the speed of the fastest electron will be
View Solution
Q4
Radiation of wavelength λ is incident on a photocell. The fastest emitted electron has a speed v. If the wavelength is changed to 3λ4, the speed of the fastest emitted electron will be :
View Solution
Q5
In a photoemissive cell with exciting wavelength λ, the fastest electron has speed v. If the exciting wavelength is changed by 3λ/4, the speed of the fastest emitted electron will be :
View Solution