In a plant, three dominant independently assorting genes A, B and C are essential for production of purple pigment. If any of the genes or all three genes are present in recessive condition then flower is colourless. Raw material A→XB→YC→Z pigment A purple plant with genotype AABBCC cossed with a clourless plant with genotype aabbcc gives purple F1 hybrid. On selfing of F1, what will be the proportion of coloured offspring in F2?
2764
964
3764
164
A
964
B
164
C
3764
D
2764
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Solution
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In
the given case, inheritance is controlled by three genes. So, it is a case of
polygenic inheritance. In this type of inheritance, the dominant alleles have
cumulative effect with each dominate allele expressing a part of the trait, the
full being shown only when all the dominant alleles are present.
In this case,
during the selfing of F1, AaBbCc results in the formation of 8 kinds of
gametes in each sex which gives 64 combinations in F2 having 7 phenotypes.
Out of these 64 combinations, only 27 combinations will show coloured
offspring. So, its proportion will be 2764.
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