Question

# In a p-n junction the depletion region is 400 nm wide and electric field of 5×105 Vm−1 exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is

A
4 eV
B
5 eV
C
0.4 eV
D
0.2 eV
Solution
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#### Given that:E=5×105d=400 nm=4×10−7 m

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