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Standard XII
Physics
Mechanism of Formation of P-N Junction
Question

In a p-n junction the depletion region is 400 nm wide and electric field of 5×105 Vm−1 exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is
  1. 4 eV
  2. 5 eV
  3. 0.4 eV
  4. 0.2 eV

A
4 eV
B
5 eV
C
0.4 eV
D
0.2 eV
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Solution
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Given that:
E=5×105
d=400 nm=4×10−7 m

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