In a p-n junction the depletion region is 400nm wide and electric field of 5×105Vm−1 exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is

4eV

5eV

0.4eV

0.2eV

A

4eV

B

5eV

C

0.4eV

D

0.2eV

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Solution

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Given that: E=5×105 d=400nm=4×10−7m

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