In a p-n junction the depletion region is 400nm wide and electric field of 5×105Vm−1 exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is
A
4eV
B
5eV
C
0.4eV
D
0.2eV
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Solution
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Given that: E=5×105 d=400nm=4×10−7m
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