In a process- 701 J of heat is absorbed by a system and 394 J of work is done by the system- What is the change in internal energy the process-

Question

Toppr Admin · Accepted Answer

System absorbs 701J of heat which has positive sign and does 394J of work which has negative sign-According to the first law of thermodynamics-x394-U-q-w-701-x2212-394-307J-

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

System absorbs $701 J$ of heat which has positive sign and does $394 J$ of work which has negative sign.
According to the first law of thermodynamics,
$Δ U = q + w = 701 - 394 = 307 J$ .

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

System absorbs 701J of heat which has positive sign and does 394J of work which has negative sign.According to the first law of thermodynamics,ΔU=q+w=701−394=307J.

System absorbs $701 J$ of heat which has positive sign and does $394 J$ of work which has negative sign.
According to the first law of thermodynamics,
$Δ U = q + w = 701 - 394 = 307 J$ .