Question

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Updated on : 2022-09-05

Solution

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Correct option is A)

$t=0$

$dtdN =2(λ_{1}+λ_{2})×N$$log_{e}(N_{0}N )=−(λ_{1}+λ_{2})t$

$2.3×log_{10}(N_{0}/100N_{0} )=5×10_{−10}t$

$5×10_{−10}2.303×2 =t$

$2.303×0.4×10_{10}=t$

$t=9.2×10_{9}$ year.

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