In a right angled triangle- one of the acute angle exceeds the other by 20-circ- Find the measure of both the acute angles in the right angled triangle-35-circ- 35-circ-35-circ- 25-circ-35-circ- 55-circ-35-circ- 75-circ-

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Toppr Admin · Accepted Answer

LetxoneacuteangleTheotheracuteangle-x-20Sumoftheangles-180x-x-20-90-180-xA0- -xA0- -xA0- -As in right angled triangle- one angle is 90-2x-70x-35-x2218-Otheracuteangle-35-20-55-x2218-

In a right angled triangle, one of the acute angle exceeds the other by $20^{\circ}$ . Find the measure of both the acute angles in the right angled triangle.
$35^{\circ}, 35^{\circ}$
$35^{\circ}, 25^{\circ}$
$35^{\circ}, 55^{\circ}$
$35^{\circ}, 75^{\circ}$

$L e t x o n e a c u t e a n g l e$

$T h e o t h e r a c u t e a n g l e = x + 20$

$S u m o f t h e a n g l e s = 180$

$x + x + 20 + 90 = 180$ ....... (As in right angled triangle, one angle is 90)

$2 x = 70$

$x = 35^{\circ}$

$O t h e r a c u t e a n g l e = 35 + 20 = 55^{\circ}$

In a right angled triangle, one of the acute angle exceeds the other by 20∘. Find the measure of both the acute angles in the right angled triangle.35∘,35∘35∘,25∘35∘,55∘35∘,75∘

LetxoneacuteangleTheotheracuteangle=x+20Sumoftheangles=180x+x+20+90=180 ....... (As in right angled triangle, one angle is 90)2x=70x=35∘Otheracuteangle=35+20=55∘

In a right angled triangle, one of the acute angle exceeds the other by $20^{\circ}$ . Find the measure of both the acute angles in the right angled triangle.
$35^{\circ}, 35^{\circ}$
$35^{\circ}, 25^{\circ}$
$35^{\circ}, 55^{\circ}$
$35^{\circ}, 75^{\circ}$

$L e t x o n e a c u t e a n g l e$

$T h e o t h e r a c u t e a n g l e = x + 20$

$S u m o f t h e a n g l e s = 180$

$x + x + 20 + 90 = 180$ ....... (As in right angled triangle, one angle is 90)

$2 x = 70$

$x = 35^{\circ}$

$O t h e r a c u t e a n g l e = 35 + 20 = 55^{\circ}$