Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Physics
Resonance in RLC Circuit
Question

In a series resonant LCR circuit, the voltage across R is 100 volts and R=1k Ω with C=2 μF. The resonant frequency is 200 rad/s. At resonance the voltage across L is
  1. 40 V
  2. 250 V
  3. 4 x 10−3 V
  4. 2.5 x 10−2 V

A
2.5 x 10−2 V
B
250 V
C
4 x 10−3 V
D
40 V
Open in App
Solution
Verified by Toppr

The resonant angular frequency , ω=1√LC

L=1ω2C=12002×2×10−6=12.5H

At resonance , impedance Z=R so the current in the circuit is

I=VZ=VR=1001000=0.1A

Voltage across inductor, VL=IXL=IωL=0.1×200×12.5=250V

Was this answer helpful?
9
Similar Questions
Q1
In a series resonant LCR circuit, the voltage across R is 100 volts and R=1k Ω with C=2 μF. The resonant frequency is 200 rad/s. At resonance the voltage across L is
View Solution
Q2
In a series LCR circuit, R=1Ω,C=2μF and voltage across R is 100 V. The resonant frequency of the circuit ω is 200 rads−1. Calculate the value of voltage across L at resonance.
View Solution
Q3
In a series resonant L-C-R circuit, the voltage across R is 100 V and R=1kΩ with C=2μF. The resonant frequency is 200 rads−1. At resonance the voltage across L is :
View Solution
Q4
In a series resonant LCR circuit, the voltage across resistor R is 100 V and R=1 kΩ with C=2 μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is
View Solution
Q5
A series LCR circuit containing a resistance of 120 ohm has angular resonance frequency 4 x 103rads−1. At resonance, the voltage across resistance and inductance are 60V and 40V respectively. The values of L and C are respectively :
View Solution