Question

In a temperature scale called Z the boiling point of water is 65 Z and the freezing point is 14 Z. Then the temperature T = -98Z corresponds on the Fahrenheit scale to -

• A. -291F
• B. -259F
• C. 179F
• D. none of these

Answer 1

Answer: (D)

Given:

In z scale,

Boiling point of water = 65Z

Freezing point = 14Z

Solution:

In Fahrenheit scale,

Boiling point of water =212 °F

Freezing point of water = 32°F

$\frac{n-32}{212-32}=\frac{-98+14}{65+14}$

$\Rightarrow \frac{n-32}{180}=\frac{-84}{79}$

$\Rightarrow n-32=\frac{-84}{79}\times 180$

$\Rightarrow n-32=-191.39$

$\Rightarrow n=32-191.39$

Therefore, n= -159.39 F

Hence, D is correct option(None of these).