In a trapezium PQRS- PQ parallel RS- and angle P - 70-circ- and angle Q - 80-circ- Calculate the measure of angle S and angle R

Question

Toppr Admin · Accepted Answer

In the trapezium PQRS- -x2220-P -x2220-S - 180-x2218- -Supplementary angles-x2220-S - 180-x2218-x2212-70-x2218-110-x2218-x2220-Q - -x2220-R - 180-x2218- -Supplementary angles-x2220-R - 180-x2218-x2212-80-x2218- - 100-x2218-

In a trapezium $P Q R S, P Q ∥ R S$ ; and $∠ P = 70^{\circ}$ and $∠ Q = 80^{\circ}$ . Calculate the measure of $∠ S$ and $∠ R$

In the trapezium $P Q R S$ , $∠ P$ + $∠ S$ = $180^{\circ}$ (Supplementary angles)
$∠ S$ = $180^{\circ} - 70^{\circ} = 110^{\circ}$
$∠ Q$ + $∠ R$ = $180^{\circ}$ (Supplementary angles)
$∠ R$ = $180^{\circ} - 80^{\circ}$ = $100^{\circ}$

In a trapezium PQRS,PQ∥RS; and ∠P=70∘ and ∠Q=80∘. Calculate the measure of ∠S and ∠R

In the trapezium PQRS, ∠P +∠S = 180∘ (Supplementary angles) ∠S = 180∘−70∘=110∘ ∠Q + ∠R = 180∘ (Supplementary angles) ∠R = 180∘−80∘ = 100∘

In a trapezium $P Q R S, P Q ∥ R S$ ; and $∠ P = 70^{\circ}$ and $∠ Q = 80^{\circ}$ . Calculate the measure of $∠ S$ and $∠ R$

In the trapezium $P Q R S$ , $∠ P$ + $∠ S$ = $180^{\circ}$ (Supplementary angles)
$∠ S$ = $180^{\circ} - 70^{\circ} = 110^{\circ}$
$∠ Q$ + $∠ R$ = $180^{\circ}$ (Supplementary angles)
$∠ R$ = $180^{\circ} - 80^{\circ}$ = $100^{\circ}$