In a triangle ABC median AD is produced to X such that AD-DX- Prove that ABXC is a parallelogram-

Question

Toppr Admin · Accepted Answer

Given that AD-DXAlso BD-DC -because of median bisector that side of -x25B3- -This show that diagonal AX and BC of -x25B3-AB-xD7-C bisect each other at D which is property of 11-xA0-gram-xA0-Thus AB-xD7-C is a parallelogram-xA0-

In a triangle $A B C$ median $A D$ is produced to $X$ such that $A D + D X$ . Prove that $A B X C$ is a parallelogram.

Given that $A D = D X$
Also $B D = D C$ (because of median bisector that side of $△$ )
This show that diagonal $A X$ and $B C$ of $△ A B \times C$ bisect each other at $D$ which is property of $11 g r a m$
Thus $A B \times C$ is a parallelogram

In a triangle ABC median AD is produced to X such that AD+DX. Prove that ABXC is a parallelogram.

Given that AD=DXAlso BD=DC (because of median bisector that side of △ )This show that diagonal AX and BC of △AB×C bisect each other at D which is property of 11 gram Thus AB×C is a parallelogram

In a triangle $A B C$ median $A D$ is produced to $X$ such that $A D + D X$ . Prove that $A B X C$ is a parallelogram.

Given that $A D = D X$
Also $B D = D C$ (because of median bisector that side of $△$ )
This show that diagonal $A X$ and $B C$ of $△ A B \times C$ bisect each other at $D$ which is property of $11 g r a m$
Thus $A B \times C$ is a parallelogram