In a uniform electric field a charge of $3 C$ experiences a force of $3000 N$ . The potential difference between two points $1 c m$ apart along the electric lines of force will be:

Question

In a uniform electric field a charge of 3 C experiences a force of 3000N- The potential difference between two points 1 cm apart along the electric lines of force will be-10V30V100V300V

Toppr Admin · Accepted Answer

Given force -3000N-xA0-on -xA0-3CWe know F-qE-x21D2-E-FqE-30003 -1000

In a uniform electric field a charge of $3 C$ experiences a force of $3000 N$ . The potential difference between two points $1 c m$ apart along the electric lines of force will be:

$10 V$
$30 V$
$100 V$
$300 V$

Given force $= 3000 N$ on $3 C$
We know F $= q E$
$\Rightarrow E = \frac{F}{q}$

$E = \frac{3000}{3}$ $= 1000$

In a uniform electric field a charge of 3C experiences a force of 3000N. The potential difference between two points 1cm apart along the electric lines of force will be:10V30V100V300V

Given force =3000N on 3CWe know F=qE⇒E=FqE=30003 =1000

In a uniform electric field a charge of $3 C$ experiences a force of $3000 N$ . The potential difference between two points $1 c m$ apart along the electric lines of force will be:

$10 V$
$30 V$
$100 V$
$300 V$

Given force $= 3000 N$ on $3 C$
We know F $= q E$
$\Rightarrow E = \frac{F}{q}$

$E = \frac{3000}{3}$ $= 1000$