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Question

In a vacuum diode, 2×1019 electrons emitted from the cathode reach the plate of a vacuum diode in 4 seconds. Find the current and the power consumed if the potential difference between the cathode and the plate is 200V.
  1. 0.8A,160W
  2. 0.8A,16W
  3. 0.8A,1.6W
  4. 0.8A,1600W

A
0.8A,160W
B
0.8A,16W
C
0.8A,1600W
D
0.8A,1.6W
Solution
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The correct option is A 0.8A,160W

I=qt

=2×1019×1.6×10194

=0.8A

Power=VI

=200×0.8=160W

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