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In a Youngs double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.

Solution
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Distance between the slits, d=0.28×103 m
Distance between the slits and the screen, D=1.4m
Distance between the central fringe and the fourth (n=4) fringe,
u=1.2×102 m
In case of a constructive interference, we have the relation for the distance between the two fringes as:
u=nλD/d
λ=ud/nD=6×107m=600nm

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