Question

In ( $$ \triangle ABC , AB = BC $$ and $$ | B = 64^{\circ} $$ find | $$\angle C$$

Answer 1

$$ AB = BC $$ [data ]
$$\therefore \angle C = \angle A $$ [ Theorem | ]
$$\angle A + \angle B + \angle C = 180^{\circ}$$
( Sum of the angle of a triangle is $$180^{\circ}$$)
$$\angle C + 64 + \angle C = 180^{\circ} [ \angle A = \angle C ]$$
$$64 + 2\angle C = 180^{\circ}$$
$$ 2 \angle C = 116 $$
$$ \angle C = \dfrac{116}{2} = 58^{\circ}$$