In above shown figure- a ball of mass m strike the wall with velocity V and rebounds back with same velocity- Calculate the change in momentum-2m-V directed to the leftm-V directed to the leftZero2m-V directed to the rightm-V directed to the right

Question

Toppr Admin · Accepted Answer

Initial momentum -mV and after rebound from the wall the final momentum -x2212-mV -xA0-negative sign is due to V is opposite to initial V -So change in momentum -x2212-mV-x2212-mV-x2212-2mV-xA0-The negative sign indicates it is directed to -xA0-left-

In above shown figure, a ball of mass m strike the wall with velocity $V$ and rebounds back with same velocity. Calculate the change in momentum.

$2 m V$ directed to the left
$m V$ directed to the left
Zero
$2 m V$ directed to the right
$m V$ directed to the right

Initial momentum $= m V$ and after rebound from the wall the final momentum $= - m V$ (negative sign is due to V is opposite to initial V )
So change in momentum $= - m V - (m V) = - 2 m V$
The negative sign indicates it is directed to left.

In above shown figure, a ball of mass m strike the wall with velocity V and rebounds back with same velocity. Calculate the change in momentum.2mV directed to the leftmV directed to the leftZero2mV directed to the rightmV directed to the right

Initial momentum =mV and after rebound from the wall the final momentum =−mV (negative sign is due to V is opposite to initial V )So change in momentum =−mV−(mV)=−2mV The negative sign indicates it is directed to left.

In above shown figure, a ball of mass m strike the wall with velocity $V$ and rebounds back with same velocity. Calculate the change in momentum.

$2 m V$ directed to the left
$m V$ directed to the left
Zero
$2 m V$ directed to the right
$m V$ directed to the right

Initial momentum $= m V$ and after rebound from the wall the final momentum $= - m V$ (negative sign is due to V is opposite to initial V )
So change in momentum $= - m V - (m V) = - 2 m V$
The negative sign indicates it is directed to left.