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Laws of Motion
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Newton's Second Law of Motion
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In above shown figure, a ball of mass m
Question
In above shown figure, a ball of mass m strike the wall with velocity
V
and rebounds back with same velocity. Calculate the change in momentum.
A
2
m
V
directed to the left
B
m
V
directed to the left
C
Zero
D
m
V
directed to the right
E
2
m
V
directed to the right
Medium
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Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is A)
Initial momentum
=
m
V
and after rebound from the wall the final momentum
=
ā
m
V
Ā (negative sign is due to V is opposite to initial V )
So change in momentum
=
ā
m
V
ā
(
m
V
)
=
ā
2
m
V
Ā
The negative sign indicates it is directed to Ā left.
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