In an a.c. circuit, the instantaneous e.m.f. and current are given by e=100sin30t, i=20sin(30t−π4). In one cycle of a.c., the average power consumed by the circuit and the wattles current are, respectively.
50√2,0
50,0
50,10
1000√2,10
A
50,10
B
50√2,0
C
50,0
D
1000√2,10
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Solution
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The correct option is D1000√2,10 Pavg=VrmsIrmscosθ
=(Vo√2)(Io√2)cosθ
=(100√2)(20√2)cos45
=1000√2watt
Wattless current = Irmssinθ
= Io√2sinθ
= 20√2sin45
= 10amp
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