Let A and B denote the events that a randomly chosen student passes first and second examinations respectively.
Then,
$$P\left(A\right)=0.8$$
$$ P\left(B\right)=0.7$$
$$P\left(A\cup B\right)=0.95$$
Required probability $$= P\left(A\cap B\right)$$ $$=$$$$ P\left(A\right)+ P\left(B\right)- \left(A\cup B\right)$$
$$=0.8+0.7-0.95=0.55$$