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Question

In an examination , a student has to secure 48% marks to pass . If Rahul gets 247 marks and fails by 5 marks , what are the maximum marks ?

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Solution

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Let the maximum marks be $x$ .

Therefore,

$\frac{48}{100} \times x = 247 + 5$

$\frac{48}{100} \times x = 252$

$x = \frac{252 \times 100}{48} = 525$

Therefore,

Maximum marks are $525.$

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