0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# In an isolated parallel-plate capacitor of capacitance C, the four surface have charges Q1,Q2,Q3 and Q4 as shown. The potential difference between the plates is :Q1+Q2C∣∣∣Q2C∣∣∣∣∣∣Q3C∣∣∣1C[(Q1+Q2)−(Q3−Q4)]

A
Q3C
B
Q1+Q2C
C
Q2C
D
1C[(Q1+Q2)(Q3Q4)]
Solution
Verified by Toppr

#### The potential difference between the plates is depend on the charge on the inner face of the plates. For parallel plate capacitor, Q2=−Q3 or Q3=−Q2Thus the potential difference between the plates is V=|Q2C| or V=|Q3C|

0
Similar Questions
Q1
In an isolated parallel-plate capacitor of capacitance C, the four surface have charges Q1,Q2,Q3 and Q4 as shown. The potential difference between the plates is :

View Solution
Q2
An isolated parallel plate capacitor of capacitance C has four surfaces with charges Q1, Q2, Q3 and Q4 as shown in the figure below. The potential difference across plates is (In the given diagram, Q1 and Q4 are the charges on the outer surfaces of the left & right plates respectively)

View Solution
Q3
q1,q2,q3 and q4 are point charges located at points as shown in the figure and S is spherical Gaussian surface of radius R. Which of the following is true according to the Gauss’s law.

View Solution
Q4
Assertion :Four point charges q1, q2, q3 and q4 are as shown in figure. The flux over the shown Gaussian surface depends only on charges q1 and q2. Reason: Electric field at all points on Gaussian surface depends only charges q1 and q2.

View Solution
Q5
Show that 1q1xq1q2+x2q2q3x3q3q4+ is equal to the continued fraction 1a1+xa2+xa3+xa4+, where q1,q2,q3, are the denominators of the successive convergents.
View Solution