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>> $In an isolated parallel - plate capacito$

Question

In an isolated parallel-plate capacitor of capacitance C, the four surface have charges $Q_{1}, Q_{2}, Q_{3}$ and $Q_{4}$ as shown. The potential difference between the plates is :

144940

This question has multiple correct options

A

$\frac{Q _{1} + Q _{2}}{C}$

B

$∣ ∣ ∣ ∣ ∣ \frac{Q _{2}}{C} ∣ ∣ ∣ ∣ ∣$

C

$∣ ∣ ∣ ∣ ∣ \frac{Q _{3}}{C} ∣ ∣ ∣ ∣ ∣$

D

$\frac{1}{C} [(Q_{1} + Q_{2}) - (Q_{3} - Q_{4})]$

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Updated on : 2022-09-05

Solution

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Correct options are B) and C)

The potential difference between the plates is depend on the charge on the inner face of the plates.
For parallel plate capacitor, $Q_{2} = - Q_{3}$ or $Q_{3} = - Q_{2}$
Thus the potential difference between the plates is $V = ∣ \frac{Q _{2}}{C} ∣$ or $V = ∣ \frac{Q _{3}}{C} ∣$

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