In an LCR circuit- capacitance is changed from C to 2C- For the resonant frequency to remain unchanged- the inductance should be changed from L to - 4L2LL-2L-4

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Toppr Admin · Accepted Answer

Resonant frequency-xA0-fr-12-x3C0-x221A-LCAs the frequency is unchanged so-xA0-fr-f-x2032-rLC-L-x2032-C-x2032-L-x2032-2C-L-x2032-L2

In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to :
4L
2L
L/2
L/4

$Resonant frequency, f_{r} = \frac{1}{2 π \sqrt{L C}}$

$As the frequency is unchanged so f_{r} = f_{r}^{'}$

$L C = L^{'} C^{'} = L^{'} (2 C)$

$L^{'} = \frac{L}{2}$

In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to : 4L2LL/2L/4

Resonant frequency, fr=12π√LCAs the frequency is unchanged so fr=f′rLC=L′C′=L′(2C)L′=L2

In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to :
4L
2L
L/2
L/4

$Resonant frequency, f_{r} = \frac{1}{2 π \sqrt{L C}}$

$As the frequency is unchanged so f_{r} = f_{r}^{'}$

$L C = L^{'} C^{'} = L^{'} (2 C)$

$L^{'} = \frac{L}{2}$