In an LCR series a-c- circuit- the voltage across each of the components- L- C and R is 50 V- The voltage across the LC combination will be- 50 text-V-50sqrt-2-mathrm-v-100 text-V-0mathrm-V- -zero-

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Toppr Admin · Accepted Answer

In a series LCR circuit- the voltage across the inductor -L- and the capacitor -C- are in-opposite phase-xA0-So the voltage across LC combination will be -50-x2212-50-0 V

In an LCR series a.c. circuit, the voltage across each of the components. L, C and R is 50 V. The voltage across the LC combination will be;
$50 V$
$50 \sqrt{2} v$
$100 V$
$0 V$ (zero)

In a series LCR circuit, the voltage across the inductor (L) and the capacitor (C) are in opposite phase.
So the voltage across LC combination will be $(50 - 50) = 0$ V

In an LCR series a.c. circuit, the voltage across each of the components. L, C and R is 50 V. The voltage across the LC combination will be; 50 V50√2v100 V0V (zero)

In a series LCR circuit, the voltage across the inductor (L) and the capacitor (C) are in opposite phase. So the voltage across LC combination will be (50−50)=0 V

In an LCR series a.c. circuit, the voltage across each of the components. L, C and R is 50 V. The voltage across the LC combination will be;
$50 V$
$50 \sqrt{2} v$
$100 V$
$0 V$ (zero)

In a series LCR circuit, the voltage across the inductor (L) and the capacitor (C) are in opposite phase.
So the voltage across LC combination will be $(50 - 50) = 0$ V