In aqueous solution- H-2- will not reduce-Fe-3-Ag-Cu-2-Zn-2-

Question

Toppr Admin · Accepted Answer

According to standard electrode- apart form Zn-2 all other ion have higher reduction potential than H- so- they can be reduced by H2 but as Zn-2 has lower reduction potential than H- so it can not be reduced by H2-

In aqueous solution, $H_{2}$ will not reduce:
$F e^{3 +}$
$A g^{+}$
$C u^{2 +}$
$Z n^{2 +}$

According to standard electrode, apart form $Z n^{+ 2}$ all other ion have higher reduction potential than $H^{+}$ so, they can be reduced by $H_{2}$ but as $Z n^{+ 2}$ has lower reduction potential than $H^{+}$ so it can not be reduced by $H_{2}$ .

In aqueous solution, H2 will not reduce:Fe3+Ag+Cu2+Zn2+

According to standard electrode, apart form Zn+2 all other ion have higher reduction potential than H+ so, they can be reduced by H2 but as Zn+2 has lower reduction potential than H+ so it can not be reduced by H2.

In aqueous solution, $H_{2}$ will not reduce:
$F e^{3 +}$
$A g^{+}$
$C u^{2 +}$
$Z n^{2 +}$

According to standard electrode, apart form $Z n^{+ 2}$ all other ion have higher reduction potential than $H^{+}$ so, they can be reduced by $H_{2}$ but as $Z n^{+ 2}$ has lower reduction potential than $H^{+}$ so it can not be reduced by $H_{2}$ .