In $β^{-}$ decay, a

Question

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Answer 1

The reaction of beta decay is shown as :
$n \to p + e^{-} + \overset{ν}{ˉ}_{e}$ (antineutrino)

So, in a $β -$ decay, a neutron converts into a proton emitting antineutrino.

option (A) is correct.

Answer 2

The reaction of beta decay is shown as :

n \to p + e^{-} + \overset{ν}{ˉ}_{e}

(antineutrino)

So, in a

β -

decay, a neutron converts into a proton emitting antineutrino.

option (A) is correct.

In $β^{-}$ decay, a

neutron converts into a proton emitting antineutrino.

neutron converts into a proton emitting neutrino.

proton converts into a neutron emitting antineutrino.

proton converts into a neutron emitting neutrino.

The reaction of beta decay is shown as :
$n \to p + e^{-} + \overset{ν}{ˉ}_{e}$ (antineutrino)

So, in a $β -$ decay, a neutron converts into a proton emitting antineutrino.

option (A) is correct.

In the $β - d e c a y$ of a radioactive nucleus :

$z^{X^{A}}$ undergoes $2 α -$ decays. $2 β -$ decays and $2 γ -$ decays and the daughter product is $z - 2^{Y^{A - 8}}$

In $α -$ decay the mass number decreases by $4$ and atomic number decreases by $2$ In $β -$ decay the mass number remains unchanged, but atomic number increases by $1$ only.

$z^{X^{A}}$ undergoes $2 α -$ decays. $2 β -$ decays and $2 γ -$ decays and the daughter product is $z - 2^{Y^{A - 8}}$

During a negative beta decay.

In both $β - d e c a y$ processes, the mass number of a nucleus remains same whereas the atomic number Z increases by one in $β - d e c a y$ and decreases by one in $β^{+}$ decay. Explain, giving reason.

Answer the following question:
Write the process of $β^{-}$ decay. How can radioactive nuclei emit $β -$ particles even though they do not contain them ? Why do all electrons emitted during $β -$ decay not have the same energy ?

Revise with Concepts

Alpha Decay

Alpha Decay - Problems L1

Beta Decay

Gamma Decay

In β− decay, a

neutron converts into a proton emitting antineutrino.

neutron converts into a proton emitting neutrino.

proton converts into a neutron emitting antineutrino.

proton converts into a neutron emitting neutrino.

The reaction of beta decay is shown as :n→p+e−+νˉe​ (antineutrino) So, in a β− decay, a neutron converts into a proton emitting antineutrino. option (A) is correct.

In the β−decay of a radioactive nucleus :

zXA undergoes 2α− decays. 2β− decays and 2γ− decays and the daughter product is z−2YA−8

In α− decay the mass number decreases by 4 and atomic number decreases by 2 In β− decay the mass number remains unchanged, but atomic number increases by 1 only.

zXA undergoes 2α− decays. 2β− decays and 2γ− decays and the daughter product is z−2YA−8

During a negative beta decay.

In both β−decay processes, the mass number of a nucleus remains same whereas the atomic number Z increases by one in β−decay and decreases by one in β+ decay. Explain, giving reason.

Answer the following question: Write the process of β− decay. How can radioactive nuclei emit β−particles even though they do not contain them ? Why do all electrons emitted during β−decay not have the same energy ?

Revise with Concepts

Alpha Decay

Alpha Decay - Problems L1

Beta Decay

Gamma Decay

In $β^{-}$ decay, a

The reaction of beta decay is shown as :
$n \to p + e^{-} + \overset{ν}{ˉ}_{e}$ (antineutrino)

So, in a $β -$ decay, a neutron converts into a proton emitting antineutrino.

option (A) is correct.

In the $β - d e c a y$ of a radioactive nucleus :

$z^{X^{A}}$ undergoes $2 α -$ decays. $2 β -$ decays and $2 γ -$ decays and the daughter product is $z - 2^{Y^{A - 8}}$

In $α -$ decay the mass number decreases by $4$ and atomic number decreases by $2$ In $β -$ decay the mass number remains unchanged, but atomic number increases by $1$ only.

$z^{X^{A}}$ undergoes $2 α -$ decays. $2 β -$ decays and $2 γ -$ decays and the daughter product is $z - 2^{Y^{A - 8}}$

In both $β - d e c a y$ processes, the mass number of a nucleus remains same whereas the atomic number Z increases by one in $β - d e c a y$ and decreases by one in $β^{+}$ decay. Explain, giving reason.

Answer the following question:
Write the process of $β^{-}$ decay. How can radioactive nuclei emit $β -$ particles even though they do not contain them ? Why do all electrons emitted during $β -$ decay not have the same energy ?