In comparing e-m-f-s of 2 cells with the of potentiometer- the balance point- the current flowing through the wire is taken from-3- Battery in the main circuit2- both of these cells1- Any one of these cells4- From an unknown

Question

Toppr Admin · Accepted Answer

Emf of secondary cell -I-xA0-r-xA0-lwhereI - current in the main circuit from battery-r - resistance per unit length of wire-l - balancing length-

In comparing e.m.f.s of 2 cells with the help of potentiometer, at the balance point, the current flowing through the wire is taken from:
3) Battery in the main circuit
2) both of these cells
1) Any one of these cells
4) From an unknown source

emf of secondary cell $= I r l$
where
I - current in the main circuit from battery.
r - resistance per unit length of wire.
l - balancing length.

In comparing e.m.f.s of 2 cells with the help of potentiometer, at the balance point, the current flowing through the wire is taken from:3) Battery in the main circuit2) both of these cells1) Any one of these cells4) From an unknown source

emf of secondary cell =I r lwhereI - current in the main circuit from battery.r - resistance per unit length of wire.l - balancing length.

In comparing e.m.f.s of 2 cells with the help of potentiometer, at the balance point, the current flowing through the wire is taken from:
3) Battery in the main circuit
2) both of these cells
1) Any one of these cells
4) From an unknown source

emf of secondary cell $= I r l$
where
I - current in the main circuit from battery.
r - resistance per unit length of wire.
l - balancing length.