In Delta ABC- AB-AC and AD is perpendicular bisector of BC- The property by which Delta ADB is not congruent to Delta ADC is -SAS propertySSS propertyRHS propertyAAA property

Question

Toppr Admin · Accepted Answer

Given that- AB-ACAs AD is perpendicular bisector to BC-xA0-So- BD-CDTherefore- -x25B3-ADB and -x25B3-ADC has one common side- two equal sides and a right angle in common-Hence- all SAS- SSS and RHS property staisfy-But AAA property does not satisfy-

In $Δ A B C, A B = A C$ and $A D$ is perpendicular bisector of $B C$ . The property by which $Δ A D B$ is not congruent to $Δ A D C$ is ______________.
SAS property
SSS property
RHS property
AAA property

Given that, $A B = A C$
As $A D$ is perpendicular bisector to $B C$
So, $B D = C D$

Therefore, $△ A D B$ and $△ A D C$ has one common side, two equal sides and a right angle in common.

Hence, all SAS, SSS and RHS property staisfy.
But AAA property does not satisfy.

In ΔABC,AB=AC and AD is perpendicular bisector of BC. The property by which ΔADB is not congruent to ΔADC is ______________.SAS propertySSS propertyRHS propertyAAA property

Given that, AB=ACAs AD is perpendicular bisector to BC So, BD=CDTherefore, △ADB and △ADC has one common side, two equal sides and a right angle in common.Hence, all SAS, SSS and RHS property staisfy.But AAA property does not satisfy.

In $Δ A B C, A B = A C$ and $A D$ is perpendicular bisector of $B C$ . The property by which $Δ A D B$ is not congruent to $Δ A D C$ is ______________.
SAS property
SSS property
RHS property
AAA property

Given that, $A B = A C$
As $A D$ is perpendicular bisector to $B C$
So, $B D = C D$

Therefore, $△ A D B$ and $△ A D C$ has one common side, two equal sides and a right angle in common.

Hence, all SAS, SSS and RHS property staisfy.
But AAA property does not satisfy.