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Question

In ΔABC and ΔDEF, AB = DF and A=D. The two triangles will be congruent by SAS axiom if :
  1. AC = DE
  2. BC = EF
  3. AC = EF
  4. BC = DE

A
BC = EF
B
BC = DE
C
AC = DE
D
AC = EF
Solution
Verified by Toppr

For triangle to be congruent SAS(Side angle Side) axiom we need to have two equal sides and the included angle same.
In ΔABC and ΔDFE
We have AB=DF
and A=D
But A is formed by the two sides AB and AC of ΔABC
But D is formed by the two sides DE and DF of ΔDFE
So we need AC=DE for the two triangles to be congruent.

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