In Delta PQR- an exterior angle R is represented by 5x - 10- If the two non-adjacent interior angles are represented by 3x - 15 and 3x - 20- the value of the exterior angle- angle R-80-o90-o84-o85-o

Question

Toppr Admin · Accepted Answer

The exterior angle is equal to the sum of the two non-adjacent interior angles-3x-15-3x-x2212-20-5x-106x-x2212-5-5x-106x-x2212-5x-10-5x-15Therefore- -x2220- R-5x-10-gt-5-xD7-15-10-85o

In $Δ$ $P Q R$ , an exterior angle at $R$ is represented by $5 x + 10$ . If the two non-adjacent interior angles are represented by $3 x + 15$ and $3 x - 20$ , find the value of the exterior angle, $∠$ $R$ .
$80^{o}$
$90^{o}$
$84^{o}$
$85^{o}$

The exterior angle is equal to the sum of the two non-adjacent interior angles.
$3 x + 15 + 3 x - 20 = 5 x + 10$
$6 x - 5 = 5 x + 10$
$6 x - 5 x = 10 + 5$
$x = 15$
Therefore, $∠$ $R = 5 x + 10 => 5 \times 15 + 10 = 85^{o}$

In Δ PQR, an exterior angle at R is represented by 5x+10. If the two non-adjacent interior angles are represented by 3x+15 and 3x−20, find the value of the exterior angle, ∠ R.80o90o84o85o

The exterior angle is equal to the sum of the two non-adjacent interior angles.3x+15+3x−20=5x+106x−5=5x+106x−5x=10+5x=15Therefore, ∠ R=5x+10=>5×15+10=85o

In $Δ$ $P Q R$ , an exterior angle at $R$ is represented by $5 x + 10$ . If the two non-adjacent interior angles are represented by $3 x + 15$ and $3 x - 20$ , find the value of the exterior angle, $∠$ $R$ .
$80^{o}$
$90^{o}$
$84^{o}$
$85^{o}$

The exterior angle is equal to the sum of the two non-adjacent interior angles.
$3 x + 15 + 3 x - 20 = 5 x + 10$
$6 x - 5 = 5 x + 10$
$6 x - 5 x = 10 + 5$
$x = 15$
Therefore, $∠$ $R = 5 x + 10 => 5 \times 15 + 10 = 85^{o}$